0
$\begingroup$

if it is difficult to discuss n!, maybe we can change n! into $\Gamma(n+1)$.

$\Gamma(z+1)=\int \limits_{0}^\infty t^ze^{-t}dt $

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.