A point D is chosen inside an equilateral triangle $ABC$ such that $AD$ = $BD$. A point $E$ outside the triangle is chosen such that $\angle DBE$ = $\angle DBC$ and $BE$ = $AB$. Find the degree measure of angle $\angle DEB$.
I first tried letting $\angle EBD$= x and trying to find the other angles in terms of x, in the hope of getting a congruent triangle. But that didn't go anywhere, or lead to anything useful. It seems that this problem requires some construction to find something equal to $E$ but I can't figure that out