0
$\begingroup$

I was wondering on how I can find the turning points of this relation:

$(x^2-7x+5)^2-y^2+7y-5=0$

The relation is two oval shapes that are seperated. Theres a desmos graph.

https://www.desmos.com/calculator/kfr2po2xxm

Thanks Braiden

$\endgroup$
  • 3
    $\begingroup$ What do you mean by turning points? You mean the "top and bottom" of the two ovals? If yes, then you have to implicitly differentiate this equation to find $\dfrac{dy}{dx}$, and then set it equal to $0$. Then you'll get the coordinates of the $4$ points. $\endgroup$ – peek-a-boo May 24 at 5:20
  • $\begingroup$ @peek-a-boo how would we do it if wanted to keep it a relation? $\endgroup$ – Elbraido Gunaratnam May 24 at 6:35

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.