I have the following homework question:
A group of order 18 has the following partial character table, where $y=-\frac{1}{2} + xi$:
\begin{array}{c | c c c c c} \hline\hline & g_1 & g_2 & g_3 & g_4 & \dots \\ \hline \chi_1 & 1 & 1 & 1 & 1 & \dots \\ \chi_2 & 1 & y & 1 & 1 & \dots \\ \chi_3 & 1 & 1 & 1 & -1 & \dots \\ \chi_4 & 2 & 2 & -1 & 0 & \dots \\ \vdots & \vdots & \vdots & \vdots & \vdots & \ddots \\ \hline \end{array}
We're first asked to calculate what y is. I know it must be an m-th root of 1, so $x = \pm \frac{\sqrt{3}}{2}$, but I can't see how to discern which it is. We're then asked to calculate five new irreducible characters to form a complete set of irreducible characters, which I have done ($\chi_5 = \chi_2 \chi_3, \; \chi_6 = \chi_2 \chi_2, \; \chi_7 = \chi_2 \chi_5, \; \chi_8 = \chi_2 \chi_4, \; \chi_9 = \chi_6 \chi_4$) and so there are 9 conjugacy classes in $G$. Finally, we're asked to complete the character table, given that the character values for $\chi_4$ are real. I've filled out the first four columns of the next five rows. I've then argued that since y is complex, $g_2 ^{-1} \not\in g_2 ^G$, and so $g_2 ^{-1} \in g_5 ^G$, say, with $\chi_i(g_5) = \overline{\chi_i(g_2)}$. I think I could now proceed using column relations, but I feel that I can probably glean more information before having to brute force it
Any hints/suggestions please?