# Calculate Triangle area using tan

I have this question:

The triangle ABC is a right angle triangle at the C corner, and have angle x at A corner. We know that the side |AB|=8 and tanx=1/3. What is the AREA of the Triangle?

I've tried to use a mix of the trigometric identites + sin2x+cos2x=1 to solve this, but I always end up with the wrong area. Any tips on how to calculate this kind of question?

The area equals to $$\frac{1}{2}*AC*BC=\frac{1}{2}AB^2*\sin x* \cos x=32*\tan x*\cos^2 x= 32*\tan x* \frac{1}{\tan^2 x+1}=9.6$$