That's a great question ! And in the beginning, examples aren't easy to find.
For the first one, there are things such as (Poincaré) homology spheres : those are spaces which have the homology of a sphere, but a nontrivial $\pi_1$. Depending on what you already know, this may or may not be easy to construct, so here's a more elementary example : take $\mathbb T = S^1 \times S^1$ on one side and $S^1\vee S^1 \vee S^2$ on the other side.
It's easy to see that their homologies are the same, but their $\pi_1$ and $\pi_2$ (and actually many others) differ.
A way to understand why examples are not too easy to find : any map between simply-connected spaces which induces an isomorphism on $H_*$ also induces one on $\pi_*$. Watch out : this is not saying that simply-connected spaces with the same $H_*$ have the same $\pi_1$ : there really has to be a map.
Can you tweak my example to see why that is ?
As for spaces with the same $\pi_*$ but not homeomorphic , this is easy : just take any non-singleton contractible space (such as $\mathbb R$) and more generally homotopy-equivalent spaces that aren't homeomorphic. So maybe you meant "same $\pi_*$ but not homotopy equivalent"
Depending on what you know, this can also be tricky, for two reasons : the first is that again any map (between nice spaces) inducing an isomorphism on $\pi_*$ is a homotopy equivalence (note that once again we require a map !).
The second reason is that, without a map, any two (nice) spaces with exactly one nonzero homotopy group, which are isomorphic, (say $\pi_n(X) \cong \pi_n(Y)$ for all $n$, and all of them are zero except for one $k$) are homotopy equivalent (those are called Eilenberg-MacLane spaces).
So with that in mind, it can be hard to find examples. If you know about the long exact sequence of a fibration, then here's one example : $S^3\times \mathbb CP^\infty$ and $S^2$ have isomorphic homotopy groups, but are not homotopy equivalent
(To see it, use the long exact sequence of the Hopf fibration $S^1\to S^3\to S^2$)
I don't know a simpler example, however, so it really depends on what you know.