Let $\alpha \leqslant \beta \leqslant \gamma$ and $$\alpha+\beta+\gamma = 9$$ $$\alpha\beta+\beta\gamma+\gamma\alpha=26$$ $$\alpha\beta\gamma=24.$$ What is $100\alpha+10\beta+\gamma$?
From Vieta's formulas we get
$$\frac{-b}{a}=9$$ $$\frac{c}{a}=26$$ $$\frac{-d}{a}=24$$
so from here we can form the cubic $f(x)=x^3-9x^2+26x-24$. My question is how can I find the roots from this cubic in order to compute the expression they asked or do I even have to find the actual roots?