I'm having a bit of an issue with solving a permutations problem
Find the number of ways in which $4$ boys and $4$ girls can be seated in a row of $8$ seats if they sit alternately. Okay, well.. Simple enough, after solving the permutations of both cases I get $1152$ permutations
There is a boy named Micah and a girl named Loretta in problem number $4$, and they cannot be seated next to each other or else they will fight. How many permutations are there now?
I'm completely stuck on this one, without any idea on how to start except for getting the number of permutations where they are sitting together.
Any help would be appreciated (not just an answer please!)