A standard six side die is rolled three times.
Find the chance that three different faces appear?
Probability p(same face pops up is)= $1- P$. You roll first one and record what you get. The probability of next (2) two rolls give you same face is...? My chances of rolling any given face is $1/6$. It does not matter what you get first role the next two rows have to the same as the first one role. Therefore$= (1-(1/6)^2)= 1-(1/6^2)=1-(1/36)$