I did find the solution to my question, and it is evidently the correct solution. However, I am not really convinced with the solution. Can someone, please help me understand and clear my doubts on this please?
The solution I found: Selecting at least 3 black balls from a set of 5 black balls in a total selection of 5 balls can be
3 B and 2 R
4 B and 1 R and
5 B and 0 R balls.
Therefore, our solution expression looks like this. 5C3 * 3C2 + 5C4 * 3C1 + 5C5 * 3C0 = 46 ways .
My Doubt: 5C3 - This means, there are 10 ways to select 3 black balls from 5 black balls, correct? But, aren't all the 10 ways same? Since all the balls are black and identical? How can there be 10 ways to select 3 balls from identically 5 black balls?