I'm asked to find the stability function and interval, and prove that the order of consistency is at least 2, of this butcher tableau:
\begin{array} {c|cccc} 1\\ -1 & 2\\ \hline & \frac{3}{4} &\frac{1}{4} \end{array}
The stability function and interval are easy to find, but the system is non autonomization invariant. This makes proving that the order of consistency is at least 2 somewhat troubling.
For the stability function:
$$k_1=f(t_j + h, y_j) = \lambda y_j$$ $$k_1=f(t_j -h, y_j + 2k_1) = \lambda (y_j + 2hk_1) = \lambda (y_j + 2h\lambda y_j)$$
$$y_{j+1} = y_j + h(\frac{3}{4}k_1 + \frac{1}{4}k_2) = y_j(1 + h \lambda + \frac{1}{2}(h\lambda)^2 ) $$ Thus the stability function is $g(z) = 1 + z + \frac{1}{2}z^2$
For the stability intervall: $|g(z)| < 1$ or $z(1 + \frac{1}{2}z) < 0$ thus $-2 < z < 0$
Now concerning the order of consistency. What was used in Find order of consistency of IVP with Butcher Tableau , Find order of consistency, stability function and stability interval of Runge-Kutta method and Find $\alpha$ such that $y_{j+1}=y_j+\frac{h}{2 \alpha}k_1 + h(1- \frac{1}{2 \alpha})k_2$ has order of consistency 2 was that the system was autonomization invariant.
That is, the left side of the upper part of the butcher tableau is equal to the sum of the elements on right side, which is not the case here ($1 \neq 0$ , $-1 \neq 2$). If a system is autonomization invariant, we simply need to derivate with respect to time. But here, that is not the case. Do I thus need to derivate with respect to both $t$ and $y$ ? Doesn't that make the whole things a lot more complicated ? Isn't there a nicer way to proceed ?
Any hint/ help would be greatly appreciated.