A famous and simple lower bounds for Stirling numbers of the second kind is as follows:
$$\binom{n}{k-1} \le {n\brace k}$$
I tried to prove that using the relation $${n\brace k}=\frac{1}{k!}\sum_{j=0}^{k}\binom{k}{j}\left(-1\right)^{j}\left(k-j\right)^n$$
But could not conclude the result.Is it possible to prove this lower bound without using induction? ( If yes then please provide the proof, if no then use induction).
Also why we the lower bound does hold for this example: $$4=\binom{4}{3}+\binom{5}{3}\color{red}{\nleq}{4\brace 4}+{5\brace 4}=1$$