0
$\begingroup$

I have the following equation $y=x|1-x|^{-1}$ And I need to rearrange this for x

I've tried many things, however I can't work out the answer

Current working:

$\frac{y}{x}=1/|1-x|$

$\frac{x}{y}=|1-x|$

$\frac{x}{y}=√((1-x)^2)$

$\endgroup$

2 Answers 2

5
$\begingroup$

Hint: assuming you're only interested in real solutions, $|1-x|$ is either $1-x$ or $-(1-x)$.

$\endgroup$
3
$\begingroup$

Hint:

If you drop the absolute value for a while, you can write

$$y=\pm\frac x{1-x}$$

which is solved by

$$x=1-\frac1{\pm y+1}.$$

Remains tp discuss in terms of the sign of $1-x$ or $\pm y+1$.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .