Context: This is with REF to some numerical calculation
Assume I know the values of $\cos(A-B)$, $A$, $\sin(A)$, and $\cos(A)$
Is there a way I can figure out $B$ without using inverse cosine?
Details and any research
I think there should be a way to use the identity $\cos(A-B) = \cos(A)\cos(B) + \sin(A)\sin(B)$ but cannot wrap my head around it to solve without going for a matrix solver.