A cone with an elliptical base can be linearly transformed into a circular cone.
Apply the same linear transformation to both the cone and the intersecting plane;
this is the same as applying the same linear transformation to the curve that is formed by the intersection of the cone and the plane.
So we transform to a circular cone, find the intersection (which is a standard conic section), and then reverse the transformation to get back to what is shown in your figure.
The linear transformations of conic sections are still conic sections.
What you show in the figure is a bounded figure, so it's either an ellipse or a circle.
What we do not know is what the transformation (to get back to your figure) did to the dimensions of that ellipse. It could have stretched or compressed the minor axis without having any effect on the lengths $AB,$ $BC,$ or $CD$.
Or it could have left the minor axis unchanged by changed all those other lengths instead. Or it could have reoriented the axes of the ellipse so that
$BC$ is not the major axis.
In short, all kinds of formulas that were derived for circular cones (right or oblique), including the formula $\frac12\sqrt{AB\cdot CD}$, go right out the window when you make the base of the cone elliptical.
You may be able to salvage some formulas by reinterpreting the elliptical cone as an oblique circular cone.
That is, for any elliptical cone, there is a set of parallel planes whose intersections with the cone are all circular. Find two of those planes at the "top" and "bottom" of your ellipse and measure $AB$ and $CD$ in those planes; then the formula should work.