I don't know how to do this I'm just curious how can I.
1 Answer
Let $x$ and $y$ be 2 real numbers. Choose $y = \sqrt{2}$ and $x = \sqrt{3}^{\sqrt{2}}$
Now there are two scenarios possible :-
$x$ is rational, in which case your proposition is proved, as x is a number which equals an irrational number raised to the power of another irrational number.
$x$ is irrational, in which case we have $x^y = 3$ being rational.