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My notes give a lemma but I,m snuggling how the lemma actually works. Any help would be appreciatedenter image description here

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    $\begingroup$ $f \leq g$ implies $\int f \leq \int g $ $\endgroup$
    – Kavi Rama Murthy
    Feb 26, 2020 at 7:51

1 Answer 1

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From $0 \le f(x) \le \frac{\lambda}{b-a}$ it follows that

$$0 = \int_a^b 0 dx \le \int_a^b f(x) dx \le \int_a^b\frac{\lambda}{b-a}= \lambda .$$

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