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Let $f:\mathbb{R}^d\rightarrow \mathbb{R}^d$ be a $L$-Lipschtiz continuous function and for every positive integer $n$ define $$ x^n = f(x^{n-1}) \mbox{ and } x^0=x, $$ for some fixed $x \in \mathbb{R}^d$. Then for $n<m$, positive integers, is there a (reasonable) bound on $$ \|x^n-x^m\| , $$ as a function of $L$, $n$, and $m$?

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    $\begingroup$ Hint: telescopic series $x^n-x^m=(x^n-x^{n+1})+(x^{n+1}-x^{n+2})+\cdots+(x^{m-1}-x^m)$ $\endgroup$ – Questioner Feb 19 at 14:44
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Hint: telescopic series $x^n-x^m=(x^n-x^{n+1})+(x^{n+1}-x^{n+2})+\cdots+(x^{m-1}-x^m)$ gives you $$\Vert x^n-x^m\Vert\leq\sum_{i=n}^{m-1}L^i\Vert x-x^1\Vert=\frac{L^n-L^m}{1-L}\Vert x-x^1\Vert.$$

This bound is tight for $f(x)=Lx$, $x^0=1$

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  • $\begingroup$ Is there a reasonable lower-bound depending on $n,m$ (non-constantly)? $\endgroup$ – AIM_BLB Feb 19 at 17:42
  • $\begingroup$ @AIM_BLB Not really. A constant function is $L$-Lipschitz but $\Vert x^n-x^m\Vert=0$ for $n,m\geq 1$. $\endgroup$ – Questioner Feb 19 at 17:58
  • $\begingroup$ Fair but suppose non-constant (or else like you said its trivial) $\endgroup$ – AIM_BLB Feb 19 at 17:59

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