Suppose that $v \in \mathbb{R}^n$ is a vector orthogonal to all vectors $x \in \mathbb{R}^n$. Prove that $v = 0$.
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$\begingroup$ Might I ask what curvy E is? Thanks. $\endgroup$– awllowerApr 7, 2013 at 7:20
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$\begingroup$ Take inner products. You can do this by looking at a general vector in $\mathbb{R}^n$ or by considering $<v,v>$. $\endgroup$– user27182Apr 7, 2013 at 11:04
4 Answers
if v is orthogonal to all of vector of R then for each standarad base we must have $v_i=v*e_i=0$ so v=0
sign * means inner product
If $v$ is orthogonal to all vectors in $\mathbb{R}^n$, then in particular it is orthogonal to itself. What does this, then, imply?
If $v$ is orthogonal to all vectors in $\mathbb R^n$, then as mentioned above $v$ is self orthogonal but then $<v,v>=0$, Now you need to know the definition of inner product (or scalar product in this case).$<v,v>=0$ $\implies v=0$