Is it possible to solve an equation such as $x^2+5^x - 10 = 0$ without using graphical methods? I tried using logarithms to find the answer to $x^2+5^x-10=0$ but I didn't have any luck. Is there a way of solving the above equation algebraically, or do you have to use a graphical method?
 A: You are looking for the zero's of function$$f(x)=x^2+5^x-10$$ which is highly transcendental. The solutions would require numerical methods or special functions. Consider its derivatives
$$f'(x)=2 x+5^x \log (5)\qquad \text{and} \qquad f''(x)=5^x \log ^2(5)+2 \quad >0 \quad \forall x$$
The solution of $f'(x)=0$ is given in terms of Lambert function
$$x_*=-\frac{1}{\log (5)}W\left(\frac{1}{2}\log ^2(5)\right)\approx -0.413583$$ For this value $f(x_*)\approx -9.31500$ and this is a minimum (by the second derivative test); then two roots on each side of $x_*$.
Let me be lazy, and consider the expansion of $f(x)$ around $x=0$. This will give
$$f(x)=-9+x \log (5)+x^2 \left(1+\frac{\log ^2(5)}{2}\right)+O\left(x^3\right)$$ giving
$$x_{1,2}=-\frac{\log(5)\pm\sqrt{36+19 \log ^2(5)}}{2+\log ^2(5)}$$ probably not very accurate but  sufficient to start Newton method. The iterates will be
$$\left(
\begin{array}{cc}
n & x_n \\
 0 & -2.3616508 \\
 1 & -3.3004059 \\
 2 & -3.1642570 \\
 3 & -3.1613032 \\
 4 & -3.1613018
\end{array}
\right)$$
$$\left(
\begin{array}{cc}
n & x_n \\
 0 & 1.6604150 \\
 1 & 1.3887413 \\
 2 & 1.3171449 \\
 3 & 1.3131011 \\
 4 & 1.3130890
\end{array}
\right)$$
A: $x^2+5^x-10=0$
$x= ± \sqrt{10-5^x}$
$10-5^x=1, 4, 9$
$10-5^x=1$  ⇒ $x=\frac{log (9)}{log (5)}=1.36$
$10-5^x=4$  ⇒ $x=\frac{log (6)}{log (5)}=1.11$
$10-5^x=9$  ⇒ $x=\frac{log (1)}{log (5)}=0$
Non of these results satisfy the equation.But we can use try and error method.We can see that x must be between $1.36$ and $1.11$, we try $x=1.3$:
$1.3^2=1.69=1-5^x$  ⇒ $x=\frac{log 8.31}{log 5}≈1.3$
