0
$\begingroup$

Apologies in advance if this was already answered somewhere, I tried searching but didn't really know what to search for which is the same issue I'm having with Google. I really appreciate your help with this!!

I need to figure out how many combinations are possible of the following sets. I think that I just multiply everything together can anyone confirm that for me?

Example 1: 5 sets of 5 options. So there's (a1, a2, a3, a4, and a5) in one set, (b1, b2, b3, b4, and b5) in the next and there's c, d, and e all with 5 in the set. To figure out all the possible combinations would that just be 5*5*5*5*5= 3125?

Do I have that right?

$\endgroup$
  • $\begingroup$ If you are selecting one element from each set, your answer is correct. $\endgroup$ – N. F. Taussig Jan 5 at 10:49
-1
$\begingroup$

If you need exactly one element of each set, and in the specific order of $\\$ a -> b -> c -> d -> e, $\\$ then yes. If not, it depends on how you pick the elements to make the new randomized set.

| cite | improve this answer | |
$\endgroup$
  • $\begingroup$ Yes, so always in that order a, b, c, d, e and only one of each set. So like (a1, b1, c1, d1, e1) is one option. So that means just multiplying together? $\endgroup$ – Paula Jan 5 at 0:17
  • $\begingroup$ Yes. In this case you can even form a 5-dimensional grid, with ordered dimensions. Each cell in the grid represents a possible arrangement, are all distincts and all the possible arrangements are listed in the grid, so take $5^5$ and it does it. $\endgroup$ – charlesleninja Jan 7 at 21:19

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.