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I am trying to derive the stationary distribution of the AR(1) process $\mathbf{x}_t = A \mathbf{x}_{t-1} + \varepsilon_t$ with $\varepsilon_t \sim \mathcal{N}(0, Q)$ and $A = \begin{pmatrix} 1 & c \\ 0 & 1 \\ \end{pmatrix}$ where $0 \le c \le 1$.

As the noise term is Gaussian, the stationary distribution will be Gaussian as well, i.e. $\lim_{t\rightarrow \infty} p(X_t) = \mathcal{N}(\mu,\Sigma)$. In this case $\mathbb{E}[x_t] = \mu = 0$. However, I run into a problem when trying to determine the covariance matrix $\Sigma$ of the stationary distribution: \begin{align} \Sigma &= A^2 Var[\mathbf{x}_{t-1}] + Var[\varepsilon_t] \\ \Leftrightarrow \Sigma &= (I - A^2)^{-1} Q \end{align} $I - A^2 = \begin{pmatrix} 0 & 2c \\ 0 & 0 \\ \end{pmatrix}$ is not invertible. From a simulation I ran, I know that $\Sigma$ converges, so I assume the stationary distribution should exist. Is there a way I can derive it analytically?

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I realized that the given AR(1) process is not wide-sense stationary as $|A| = 1$. As a result the variance of $\mathbf{x}_t$ depends on the time lag $dt$ and diverges as $dt$ goes to infinity.

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