The set of finite sets, $\{A\in\mathcal{P}(\Bbb N)~:~A~\text{finite}\}$, is a countable set. To see this, consider ordering the sets by the sum of the elements in the set.
We have then the set can be written: $\{\{1\},\{2\},\{1,2\},\{3\},\{1,3\},\{4\},\{1,4\},\{2,3\},\{5\},\{1,2,3\},\{1,5\},\{2,4\},\{6\},\dots\}$ and it is clear that this pattern can continue, eventually getting any desired finite set.
It follows that the set of co-finite sets, $\{A\in\mathcal{P}(\Bbb N)~:~\overline{A}~\text{finite}\}$, is also countable as there is an obvious bijection between this set and the previous set.
Since it is known that $\mathcal{P}(\Bbb N)$ is uncountable, that $\mathcal{P}(\Bbb N)$ is equal to the disjoint union of the set of finite sets, the set of co-finite sets, and the set of infinite and co-infinite sets, and that the union of countably many countable sets is countable, it follows that the set of sets which are both infinite and coinfinite must be uncountable as well.