Suppose that group $G_i$ acts on finite dimensional complex vector space $V_i$ with finite number of orbits for $i=1,2$. Let $G=G_1\times G_2, V=V_1\otimes_{\mathbb C} V_2$ and let $G$ act on $V$ by $(g_1,g_2).v_1\otimes v_2=(g_1v_1)\otimes (g_2v_2)$. [Edit: Here a $G$ action on $V$ means a linear representation.] Is there a general way to describe the orbits of the group action of $G$ on $V$ in terms of the orbits of the $G_i$ action on $V_i$? (Edit: if it is easier, one can assume the representation $V_i$ of $G_i$ is irreducible.)
If the above question has no general answer, here is a more concrete one. Suppose that $G_1=GL_2(\mathbb C)$ and $V_1=\mathbb C^2$. Suppose that $G_2$ acts on a complex vector space $V_2$ with 4 orbits $0, C_1,C_2,C_3$, then is there a way to describe the orbits of the natural $G_1\times G_2$ action on $V_1\otimes_{\mathbb C}V_2 $ in terms of $C_1,C_2,C_3$?
The following are some efforts I tried for the concrete example. The space $V_1\otimes V_2$ can be interpreted as $Hom_{\mathbb C}(V_1^*,V_2)\cong M_{2\times n}(\mathbb C)$, where $n=dim V_2$. The action of $G_1\times G_2$ on $Hom(V_1^*,V_2)$ is given by $(g_1,g_2).f=g_2fg_1^{-1}.$ We can consider the ranks of $f$. If $rk(f)=0,$ there is only one orbit. If $rk(f)=1$, there are 3 orbits depending on the image of $f$. But I don't know what happened if $rk(f)=2$. I am very confused about the last case. I am wondering if there is a general method to solve this kind problem.
Thanks in advance.
