# How can I find the work on a block when it is pulled up in a curve?

The problem is as follows:

The figure from below shows a force acting on block as it is pulled upwards in a curve from point $$A$$ to $$B$$. It is known that the block is pulled by a force which its modulus is $$100\,N$$. Find the work (in Joules) of such force between the points indicated. Consider that the angle given is with respect of the vertical with the floor.

The alternatives given in my book are:

$$\begin{array}{ll} 1.&143\,J\\ 2.&312\,J\\ 3.&222\,J\\ 4.&98\,J\\ 5.&111\,J\\ \end{array}$$

I attempted to decompose the force given as such:

$$F\cos 37^{\circ} \times d = W$$

But the result doesn't seem to yield an adequate result:

$$W= 100\times \sin 37^{\circ} \times 2.1= 100 \times \frac{3}{5}\times 2.1=126$$

Assuming the gravity does positive work?

$$W= 100 \times \cos 37^{\circ}= 100 \times \frac{4}{5}\times 1.2= 96$$

Anyways the sum doesn't yield the result which supposedly is option $$5$$. Can somebody help me here?

• the angle between the $d$ and $F$ should be $53$ degree? Nov 24 '19 at 14:17
• @TheStudent I made that mistake, however this doesn't really fix the issue that mades me puzzled, is how should I proceed with that tilted force?. Nov 24 '19 at 14:30
• This looks to me like a conservation of energy problem.
– Neal
Nov 24 '19 at 19:18