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I have a small question here ... If the problem has constrain (=) like this $...4x+3y=1$. how to do it in the graph to get the region ... Overlooking the original point or not?

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  • $\begingroup$ $4x + 3y = 1$ represents a line $\endgroup$ – Harsha Umapathi Nov 22 '19 at 11:47
  • $\begingroup$ That I mean , I graph it only and not care about it when determine the region ? $\endgroup$ – user619263 Nov 22 '19 at 11:51
  • $\begingroup$ @user619263 what region are you referring to ? $\endgroup$ – The Demonix _ Hermit Nov 22 '19 at 12:22
  • $\begingroup$ Bounded region ..It's called (M) sometimes $\endgroup$ – user619263 Nov 22 '19 at 12:27
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If 4X + 3Y = 1 is one of your constraints, and you are solving the problem graphically, it will mean that your solution region/Bounded region will be narrowed down to just points on the line (and not above/below it, like you would see with an inequality).

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