# Distance Euler's Line

In a triangle ABC, H, G, and O are orthocenter, centroid, and circumcenter of the triangle. If the Euler's line is parallel AC and m <(HBC) = 2m <(OCA), calculate GO if AH = a (answer: a/3)

I tried to draw the triangle and relate the properties but couldn't find a solution. We know that GH = 2GO and BG = 2GP Triangle BHG ~ POG

We have the equality of (measures of) angles: $$\widehat{HAC} =90^\circ -\hat C=\widehat{HBC}=2\cdot\widehat{OCA} = 2\cdot\widehat{OAC}\ .$$ This implies: $$\widehat{HAO} = \widehat{OAC} = \widehat{AOH}\ .$$ The triangle $$\Delta HAO$$ is thus isosceles in $$H$$, so $$HA=HO=3\cdot GO$$.
• I will use the inserted picture from the OP. Here, the angle $\widehat{HBC}=\widehat{H'BC}$ complements the angle in $C$ in the triangle $\Delta H'BC$, since $BH'$ is the height in $\Delta ABC$. So $\widehat {H'BC}+\underbrace{\widehat {H'CB}}_{=\hat C}=90^\circ$. Same applies also for the situation of $HA$ instead of $HB$ (although the full height is not drawn). Nov 9, 2019 at 23:13