# Domain of function $\tan(x^2)$

I cannot figure out how do I get the domain for function $$\tan(x^2).$$ There is a square function and a tangent function. It should be all real numbers except $$(\pi+k\pi)/2$$ but I think the exception must be different because of square function, I just don't know what it does.

• So, you don't want $x^2$ to be any of those values... (You're off a bit with those, you want odd multiples of $\pi/2$.) – David Mitra Oct 25 '19 at 17:31

Since the domain for $$\tan (x)$$ is $$x\neq \frac{\pi}2+k\pi$$ therefore for $$\tan (x^2)$$ we need
$$x^2\neq \frac{\pi}2+k\pi \implies x \neq \pm \sqrt{\frac{\pi}2+|k|\pi}$$