Does there exist a probability distribution could not be associated with a cumulative distribution function? This wiki page says

A continuous probability distribution is a probability distribution with a cumulative distribution function that is absolutely continuous. Equivalently, it is a probability distribution on the real numbers that is absolutely continuous with respect to Lebesgue measure. Such distributions can be represented by their probability density functions. If the distribution of X is continuous, then X is called a continuous random variable. There are many examples of continuous probability distributions: normal, uniform, chi-squared, and others.

It seems that the first sentence in the quotation implies that there exists some other types of probability distribution that could not be associated with a cumulative distribution function?
Is my understanding right, or I am over reading the part?
 A: Every probability distribution on $\mathbb R$ is associated to a cumulative distribution function (and every non-decreasing function $F$ with $\inf_x F(x)=0$ and $\sup_x F(x)=1$ is associated to a distribution!). The quoted text is probably using "with" to refer to the whole phrase "a cumulative distribution function that is absolutely continuous."

For the fact that every probability distribution does define a cumulative distribution function, just note that defining, for a probability measure $\mu$ on $\mathbb R$, the CDF as
$$F(x)=\mu((-\infty,x))$$
gives a perfectly good CDF - although there's a little bit of ambiguity about what you should do at point masses where $(-\infty,x)$ and $(-\infty,x]$ have different measure - but this depends on what you want from a CDF and is a very manageable caveat.
Conversely, given a non-decreasing function on $\mathbb R$, you can define a measure with the property that
$$\mu((a,b))=\left(\lim_{x\rightarrow b^-}F(x)\right) - \left(\lim_{x\rightarrow a^+}F(x)\right).$$
I won't give all the technical details of this construction, but this measure is called the Lebesgue-Stieltjes measure associated to $F$.
There's a slight issue in this association having to do with point-masses, but you can fix that by imposing conditions like right-continuity on $F$ which basically decide whether $F(x)$ includes a point mass at $x$ or not. 
