# Determining the number of blocks in a graph by the number of components and vertices.

I'm trying to show that the number of blocks in $$G$$ is equal to $$\omega$$ + $$\sum_{v \in V}(b(v)-1)$$. In this statement $$\omega$$ denotes the number of components of $$G$$ and $$b(v)$$ denotes the number of blocks of $$G$$ containing $$v$$.

Intuitively, this makes sense but I'm trying to put this together algebraically as a picture does not constitute a proof.

Any help is appreciated.

-IdleMathGuy