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At a tennis tournament, there were $2^n$ participants, and any two of them played against each other exactly one time. Prove that we can find $n+1$ players that can form a line in which everybody has defeated all the players who are behind him in the line.

How would you prove this by induction? Also what does it mean to form a line? Thanks

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    $\begingroup$ To form a line, we need to find a group of $n+1$ players, one of whom has defeated all the rest. That one can stand in front. There must be a second who defeated all the others except the first, who will stand second, and so on. Try it with small $n$. If $n=1$, there are $2$ players and you need to find $2$ of them who can stand in line. Can you? If $n=2$ there are $4$ players and you need to find $3$. Can you guarantee that? $\endgroup$ – Ross Millikan Sep 30 '19 at 3:24
  • $\begingroup$ Just in case there's a cultural gap: "A line" of people in some parts of the world is more commonly called "a queue" of people. $\endgroup$ – Brian Moehring Sep 30 '19 at 3:29
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On average, everyone wins against $(2^n-1)/2$ players, so some player, $x$, has won against $2^{n-1}$ players. Find a line of $n$ among the players $x$ beat (by induction), then put $x$ at the end of the line.

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