0
$\begingroup$

Kinda stuck in here too, would like to get some help!

Using Taylor expansion check if series :

$$ \sum_{n=1}^{\infty}\frac{1}{n}\sqrt{e^\frac{1}{n} - e^\frac{1}{n+1}} $$

converges.

How do I approach this kind of exercise? Thanks in advance!

$\endgroup$
1
  • 1
    $\begingroup$ Writen down the two Taylor expansions, subtract. Use the expression you get to show that the difference (and therefore its square root) is "small." $\endgroup$ Mar 21, 2013 at 21:01

1 Answer 1

1
$\begingroup$

Hint with $e^x\sim_0 1+x+\frac{x^2}{2}$ we have $$e^\frac{1}{n} - e^\frac{1}{n+1}\sim\frac{1}{n^2}$$ so $$\frac{1}{n}\sqrt{e^\frac{1}{n} - e^\frac{1}{n+1}}\sim\frac{1}{n^2}$$ hence we have the convergence of the series by comparaison with Riemann series.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .