Find the line that is not parallel to the other three.
$x = (2,0) + t(1,1)$
$x = (1,2) + t(-1,1)$
$x = (1,1) + t(1,-1)$
$x = (1,3) + t(-1,1)$
Not sure how to approach this as I only know how to find parallel vectors. So how can I find parallel lines? Apparently, the line that is not parallel to the other three is option 1, which I believe is because of the point (1, 1) not being a scalar multiple of the others, but what about the other point?