# Generalized inverse gamma distribution

If $$X \sim \Gamma(\alpha,\beta)$$, $$\alpha, \beta >0$$, is a $$\Gamma$$-distributed r.v. with $$f^{X}(x;\alpha,\beta)= \begin{cases} \frac{\alpha^\beta}{\Gamma(\beta)}x^{\beta-1}e^{-\alpha x}, &x > 0,\\ 0, &x \le 0,\end{cases}$$ it is a known result that $$X^r$$, $$r>0$$, has the generalized $$\Gamma$$-distribution with density $$f^{GG}(x;\alpha,\beta, \delta)= \begin{cases} \frac{\delta \alpha^\beta}{\Gamma\left(\frac{\beta}{\delta}\right)}x^{\beta-1}e^{-(\alpha x)^{\delta}}, &x > 0,\\ 0, &x \le 0,\end{cases}$$ and $$X^{-1}$$ follows the inverse $$\Gamma$$-distribution with density $$f^{IG}(x;\alpha,\beta)= \begin{cases} \frac{\alpha^\beta}{\Gamma(\beta)}\left(\frac{1}{x}\right)^{\beta+1}e^{-\frac{\alpha}{x}}, &x > 0,\\ 0, &x \le 0.\end{cases}$$

I am able to show that $$X^{-r}$$, $$r>0$$, has a density of the form $$f(x;\alpha,\beta,\delta)= \begin{cases} \frac{\delta\alpha^\beta}{\Gamma\left(\frac{\beta}{\delta}\right)}\left(\frac{1}{x}\right)^{\beta+1}e^{-\left(\frac{\alpha}{x}\right)^{\delta}}, &x > 0,\\ 0, &x \le 0.\end{cases}$$

It seems like the latter should be a known density of something like the generalized inverse $$\Gamma$$-distribution but in the literature I only find links to the Stacy- or to the Amoroso-distribution which correspond to $$f^{GG}$$.

Question : Does anyone know the name of this distribution and a reference to it?

• Are $r$ and $\delta$ the same thing? – Henry Sep 11 '19 at 16:38
• No, the reparametrization is more complicated. I just wanted to give the general form of the density. – spitzen Sep 11 '19 at 16:41
• @Henry The actual reparametrizations for $r > 0$ would look like this:$X \sim \Gamma(\alpha, \beta) \Longrightarrow X^{r} \sim GG(\alpha^r,\frac{\beta}{r},\frac{1}{r})$, $X \sim \Gamma(\alpha, \beta) \Longrightarrow X^{-r} \sim GIG(\alpha^r,\frac{\beta}{r},\frac{1}{r})$ – spitzen Sep 12 '19 at 6:47