How to calculate percentile? Is it possible to get 100 percentile? How do we calculate percentile? I think it should be calculated as:
P = Total number of candidates  
L = Number of candidates whose marks are below yours

Percentile = (L/P)*100
That means if you are the highest in the range, and there are 200,000 candidates and if your marks are same as 7 others then;  
your percentile = (199992/200000)*100 = 99.996

That means in any circumstances you can't have perfect 100 percentile.  
Then how come this is possible, see links:-
http://www.zeenews.com/news680105.html
http://economictimes.indiatimes.com/cat/two-cat-aspirants-get-100-percentile/articleshow/2685824.cms 
 A: The simple answer is rounding.
A: To put it in words, being in the 100 percentile would mean that 100% of the group has marks below yours. But since 100% of the group would include you, and your mark could never be below your mark, then 100% of the group could not be below you. Therefore you could never be in the 100 percentile.
A: There are different definitions of "percentile."
Usually a percentile is computed by first ranking all the data with 1 the lowest, 2 the next lowest, up through $N$.  (The possibility of ties is a complication but does not change the essential idea.)  Ranking from lowest to highest instead of highest to lowest is arbitrary but it gives definite rules.  However, it would be nice if the percentile computed from ranking in one direction agreed with the percentile from ranking in the other.
You can convert a rank $k$ into a percentile by:


*

*Computing $100 k /N$.  This value will range from $100/N$ through $100N/N = 100$.  Note the asymmetry: the highest is 100 but the lowest is nonzero.

*Computing $100(k-1)/N$.  This is the rule quoted in the question.  The value will range from $0$ through $100(N-1)/N \lt 100$.

*You can make the range of percentiles symmetric.  This means that the percentile corresponding to rank $k$ is $100$ minus the percentile corresponding the rank in reverse order, which is $N+1-k$.  To do this, compute $100(k-1/2) / N$.  The values range from $100/(2N)$ to $100(1 - 1/(2N))$.

*There are other ways to make the range symmetric.  For instance, compute $100(k-1)/(N-1)$.  Values range from $0$ through $100$.
(There are yet other rules, used especially for constructing probability plots, but you get the idea.)
Either using the first rule, the last rule, or rounding to the nearest percent, can produce a 100th percentile.  As I recall, Excel's function for computing percentiles can produce 100 for the top-ranked value.
A: How to project a percentile between a range of numbers:
Suppose you have a range of integers between:  5 -> 12
The current value to be calculated is 6.  What percentile is 6 in the range?  Answer:
(current - min) / (max - min)

Which breaks down to:
(6-5) / (12-5)  = (1/7) = .1429

So that means 6 is about 14% on the way between 5 and 12.  
A: What happens in case of an exam where all candidates in an exam score the same marks does that mean they are all at 0% percentile as they have 0 candidates below them ?
A: It depends. There are two definitions of percentile that I know of. If you use the "percentage below or equal to" definition, then, yes, you can have a 100th percentile. However, if you use the "percentage below" definition, then, no, you cannot have a 100th percentile. I use the first one, so I'm used to dealing with 100th percentiles.
A: For percentiles, there are actually only 99 equal partitions of the population being ranked: 1 to 99.  It is thoughtless hand waving to say there are 100 equal percentile bands when calculating percentiles.
