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So, I have to find $f(x,y)$ if the following holds:

$$f\left(x+y,\frac{y}{x}\right)= x^2-y^2$$

I thought about replacing $x+y=X$, and $y/x=Y$, but now where do I replace this $x$ and $y$ that I've found?

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  • $\begingroup$ Don't forget to accept an answer to this question. It's good policy to wait for a while to see if you get more answers before accepting, but make sure to accept an answer if you got at least one that you liked. Thanks. $\endgroup$ – Git Gud Mar 18 '13 at 21:07
  • $\begingroup$ If you get answers that are helpful, you can "accept" one answer per question, but upvote as many as you'd like. To accept an answer, just click on the $\checkmark$ to the left of the answer you'd like to accept. $\endgroup$ – Namaste Mar 18 '13 at 21:32
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Set $X=x+y,Y=\frac{y}{x}$. Can you solve for $x,y$ as functions of $X,Y$?

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    $\begingroup$ OMG,I confused it with another exercise,this is what I meant..but I still dont know where to replace it..I will edit it,thanks anyway.. $\endgroup$ – asdas Mar 18 '13 at 20:55
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    $\begingroup$ OK, good. you can easily find $x=\frac{X}{1+Y},y=\frac{XY}{1+Y}$, so that $f(X,Y)=\left( \frac{X}{1+Y} \right)^2-\left( \frac{XY}{1+Y} \right)^2$ $\endgroup$ – user1337 Mar 18 '13 at 20:58
  • $\begingroup$ Merci monsieur :) $\endgroup$ – asdas Mar 18 '13 at 21:02

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