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If I need to split 4 white identical balls and 1 green, 1 red and 1 blue balls (7 in total) to 5 different cells, when cells can be empty and you can put as much balls as you wish in each cell, with the exception that in each cell there can be a maximum of 1 white ball, how many options have I got?

Thanks

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  • $\begingroup$ by the way my answer is 625, I don't know if it's correct though $\endgroup$ – homiee Mar 18 '13 at 13:24
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There are $5$ choices for which cell the white ball isn't in. Each other ball has $5$ possibilities, so a total of $5 \times 5 \times 5 \times 5 = 625$

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