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I don't know what rationalizing factors are and I need help finding $\sqrt[5]{a^2b^3c^4}$

There are some options

A) $\sqrt[5]{a^3b^2c}$

B) $\sqrt[4]{a^3b^2c}$

C) $\sqrt[3]{a^3b^2c}$

D) $\sqrt{a^3b^2c}$

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2 Answers 2

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$\sqrt[5]{a^2b^3c^4}.\sqrt[5]{a^3b^2c}= \sqrt[5]{a^5b^5c^5}=abc.$

Therefore (A) is the correct answer.

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In your case you can't rationalize the polynomial $a^2b^3c^4$ because the fifth-root isn't further simplyficable.

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