# What are rationalizing factors?

I don't know what rationalizing factors are and I need help finding $$\sqrt[5]{a^2b^3c^4}$$

There are some options

A) $$\sqrt[5]{a^3b^2c}$$

B) $$\sqrt[4]{a^3b^2c}$$

C) $$\sqrt[3]{a^3b^2c}$$

D) $$\sqrt{a^3b^2c}$$

• What would you do with those "rationalizing factors", if you knew what they are and you had them?
– user239203
Aug 25, 2019 at 16:26
• math-only-math.com/rationalization-of-surds.html Aug 25, 2019 at 16:27

$$\sqrt[5]{a^2b^3c^4}.\sqrt[5]{a^3b^2c}= \sqrt[5]{a^5b^5c^5}=abc.$$

Therefore (A) is the correct answer.

In your case you can't rationalize the polynomial $$a^2b^3c^4$$ because the fifth-root isn't further simplyficable.