A fundamental exercise is to calculate the probability of picking 3 aces and 2 kings while randomly picking a 5-card hand out of a 52-card deck. Our sample space would be $52\cdot51\cdot50\cdot49\cdot48\over5!$, and the event would be $4! \over3!$ $\cdot$ $4!\over2!$. So far so good.
But what if we add the jokers in the deck? The probability for the hand to contain a joker would be the same as any other card (and of course the sample space should increase to 54, etc.,) but since the joker can be anything, I can't find a way to handle the rest.
Can I assume a $6!\over3!$ event probability for the aces, let's say, since there are now 6 "possible aces" (the 4 "real" aces and the 2 jokers) in the deck? But if that holds true, I can't concurrently have 6 possible kings.