Here I first drew a parabola with equation $y^2=4ax$ then according to the question I drew a tangent at point $P(at^2,2at)$ which passes through the foot of directrix ie: $T(-a,0)$ . Now I drew a circle with centre $C(h,k)$ which lies on the tangent at $P$ and also the circle passes through the the point $P$ . Now we have to prove that the circle always passes through the focus ie: $S(a,0)$

I did the following calculation

I am going wrong somewhere which I am not being able to identify. I thoroughly checked my calculation again and again but didnt find a mistake but still I am wrong in some place . It would be greatly appreciated if someone could help me find my mistake

  • $\begingroup$ Please state the problem explicitly, then explain using clear notation and a clear order of the introduced objects what was done. Two pictures, one with an unclear statement, one with a tiny raw picture and explanations with no obvious beginning and and can not substitute the needed requirements for a decent post. $\endgroup$ – dan_fulea Aug 22 '19 at 18:42
  • $\begingroup$ The question is what it is , I can't do anything about it , for the explanation though I will edit the post gladly $\endgroup$ – gucci Aug 22 '19 at 19:03

Your diagram is not correct, because you misinterpreted the text (which is indeed rather obscure). The text should read as follows:

A circle is drawn through any point $P$ on the parabola $y^2=4ax$ and through the perpendicular projection of $P$ on the directrix. The centre of the circle lies on the tangent at $P$. Prove the circle always passes through the focus.

I'd suggest you to check with GeoGebra if the diagram is correct, before starting to prove something.

The solution of this problem, by the way, can be carried out with no calculations at all, by using the properties of the parabola I reported in my answer to your previous question.

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  • $\begingroup$ Thanks @Aretino, I will surely do the required calculations and drop an update here. $\endgroup$ – gucci Aug 22 '19 at 20:19

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