# 10 + 67 × 2= ?, This question is causing a ruckus among my friend [closed]

Help!

How would you solve 10 + 67 × 2?

I solved by putting a bracket between 10 and 67. Then multiplying by 2 Like this (10 + 67)2 = 154

However, others insist it's 144 and I'm wrong.

• You multiply first, then add. This ambiguity is exactly why we use brackets. Aug 16, 2019 at 13:03
• you do the multiplication first - so it's $67\times 5=335$, then $335+10=345$. Aug 16, 2019 at 13:04
• See this Wikipedia article Aug 16, 2019 at 13:05
• I think it's only natural one adds the bracket automatically considering the way the equation was written LRT Aug 16, 2019 at 13:07
• Does $\ 10 + 67\, x\$ or other polynomials also "cause ruckus"? If not, why? Aug 16, 2019 at 13:20

You can't write $$(10+67)\cdot 2$$ (because you add a $$10$$ that doesn't exist), but if you want to use brackets, you can say: $$(67+10)\cdot 2-10=67+67+10+10-10=144$$. Or $$10=5\cdot 2$$: $$2\cdot (67+5)=144$$.
If they meant $$(10 + 67) \times 2$$, they should have written that. Otherwise one should assume the standard order of operations is meant. Go to Wolfram Alpha and put in 10 + 67 * 2. It will answer 144 because there is nothing to indicate the addition should be done first.
$$10+67\cdot5=10+335=345$$