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Find the orthogonal vectors $v_1$ and $v_2$ such that $Av_1$ and $Av_2$ are still orthogonal, where $$A = \begin{pmatrix} 1 & -1 \\ 2 & 2 \end{pmatrix}$$
What can we comment about the lengths of $Av_1$ and $Av_2$ ?
I'm stuck thinking if these $v_1$ and $v_2$ are eigenvectors of $A$. If yes how does the second condition hold, "$Av_1$ and $Av_2$ are still orthogonal"? Is it by default? Thanks in advance!
If $v_1$ and $v_2$ are eigenvectors, then $Av_1=\lambda_1v_1$ and $Av_2=\lambda_2v_2$, where $\lambda_1$ and $\lambda_2$ are the corresponding eigenvalues. So if the eigenvalues are non-zero, $Av_1=\lambda_1v_1$ and $Av_2=\lambda_2v_2$ are orthogonal if and only if the eigenvectors $v_1$ and $v_2$ are already orthogonal.
In this problem, using eigenvectors will not work since they are not orthogonal.
Instead, we can solve this problem by letting $v_1=(a, b)^T$ and $v_2=(b,-a)^T$. Then $Av_1=(a-b, 2a+2b)^T$ and $Av_2=(a+b, 2b-2a)^T$. We need $Av_1$ and $Av_2$ to be orthogonal, i.e. $(a-b)(a+b)+(2a+2b)(2b-2a)=0$. Now, solve to find a solution for $a$ and $b$.
