What is the total area enclosed between the curve $y=x^2-1$, the x-axis and the lines $x=-2$ and $x=2$?
I tried to find the area by using the integrals $\int_1^2$ and $\int_{-1}^{-2}$ .
$x^2-1$ integrated is $\frac{x^3}{3}-x$
The answer is supposed to be $4$, but by adding up $\int_1^2$ and $\int_{-1}^{-2}$ my area is $\frac{8}{3}$. What am I doing wrong?