# How to split the polynomial . [closed]

How do I split $$x^2-5$$ in $$\mathbb{Z}/5\mathbb{Z}$$ ? Since $$0$$ is a root I have $$x$$ as linear factor . How can I find the other linear factor ?

## closed as off-topic by Servaes, cmk, ronno, Adrian Keister, ThorWittichJul 22 at 20:37

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Servaes, cmk, ronno, Adrian Keister, ThorWittich
If this question can be reworded to fit the rules in the help center, please edit the question.

• $x^2=x\times x$ – J. W. Tanner Jul 21 at 20:21
• -1 This really shows very little effort; there are only $4$ other candidates for the roots, and none of them are roots. Or you could have tried polynomial long division. Or simplified $x^2-5$ to $x^2$. – Servaes Jul 22 at 11:30
• @Servaes: I'd say that this shows more effort than a lot more recent questions. – user21820 Jul 29 at 15:25
• @user21820 Regardless of the quality of other questions, I find this one deeply subpar. But feel free to link some more questions to close. – Servaes Jul 29 at 16:56
• @Servaes: Sure. You can find many here (especially in the middle and bottom). – user21820 Jul 29 at 17:42

Note that $$x^2-5 = x^2$$, which is already factorised.