The number of years a Bulldog lives is a random variable with mean 9 and standard deviation 3 , while for Chihuahuas, the mean is 15 and the standard deviation is 4 . Approximate the probability the that in a kennel of 100 Bulldogs and 100 Chihuahuas, the average Chihuahua lives at least 7 years longer than the average Bulldog.
Initially I drew a normal curve with the chihuahua distribution with the mean 15 and proceeded to find the probability that the age exceed 16 but that is giving me a very small number of .006 which does not sound correct to me. The hint is to use central limit theory. Thanks for the help.