# In a rhomboid $ABCD$ an angle bisector is $DM$ ($M\in BC)$. If $AB=6$, compute the length of the segment that joints the midpoints of $AM$ and $BD$

In a rhomboid $$ABCD$$ an angle bisector is $$DM$$ ($$M\in BC)$$. If $$AB=6$$, compute the length of the segment that joints the midpoints of $$AM$$ and $$BD$$

I don't know how to proceed in this kind of problem, i never worked with the angle bisector in a rhomboid. I tried to use the fact that sum of contiguous angles is $$180º$$, named the length of all the segments with variables and used the fact that the diagonals bisects each other, but it didn't work.

Any hints?

• If $DM$ is an angle bisector so $M\equiv B$. Jul 7 '19 at 5:33

If $$DM$$ is an angle bisector so $$M\equiv B$$, which gives the answer: $$\frac{6}{2}=3.$$