I'm messing around with the Sum of Three Cubes problem, and I'm seeing something interesting:
For the case $n=16$, all the sources I've seen are saying that the smallest solution is
$$16 = (-511)^3 + (-1609)^3 + (1626)^3$$
...But using my own very naive algorithm, I was able to find the following solution:
$$16 = (-48)^3 + (-94)^3 + (98)^3$$
Am I misunderstanding the problem in some way? Or is this something that was simply overlooked by the authors of the sources? Surely it's not a novel finding worthy of publication?