two students are selected at random one after the other without replacement, from a group of 10 students. there are 6 male students. given that the second selected student is a male, what's the probability of the first selected student is male?
since they have said the second student is male, the probability of picking a male student for the second time is P(b2) = 6/10 * 5/9 + 4/10 * 6/9 = 54/90 cause the first student isn't mentioned I took as it could be either a girl or a boy
both selected students being boys, i took it as P(b1 AND b2) = 6/10 *5/9 = 30/90
so the first boy being a boy given that second one is a boy P(b1/b2) = 5/9 this is the answer i got. can someone please tell me whether this is the correct answer and the correct way of solving this problem?