# Prove that the circumference of a circle is $25\pi$ [closed]

A regular hexagon inscribed in a circle has an area of $$54*3^\frac{1}{3} \text{sq.in}$$ Prove that the circumference of a circle is $$25\pi$$

Hint: The area of a regular $$n$$-gon inscribed in a circle of radius $$R$$ is: $$A_n=\frac n2 R^2\sin\frac{2\pi}n.$$ Can you take it from here?
Warning: the answer will appear to be different from $$25\pi$$ (in), since the latter value is wrong.