Let $U = \lbrace 1, 2, \dotsc, K \rbrace$. Now we take all possible subsets of $U$ except the null set and arrange them in $K$ tiers based on the number of elements in them. For example, for $U = \lbrace 1, 2, 3 \rbrace$, we have $3$ tiers as follows:
$T_1: \lbrace 1 \rbrace, \lbrace 2 \rbrace, \lbrace 3 \rbrace$
$T_2: \lbrace 1, 2 \rbrace, \lbrace 1, 3 \rbrace, \lbrace 2, 3 \rbrace$
$T_3: \lbrace 1, 2, 3 \rbrace$,
where index $i$ ($1 \leq i \leq K$) of $T_i$ denotes the number of elements of the sets that are in $T_i$.
Now, for a given test set in $T_i$, if we randomly choose a set in $T_j$ ($1 \leq i \leq K$), what is the probability that there are exactly $k$ elements common between the randomly chosen set in $T_j$ and the test set in $T_i$?
For example, for the test set $\lbrace 1, 2 \rbrace \in T_2$, $\lbrace 1 \rbrace$ and $\lbrace 2 \rbrace$ in $T_1$ have one element in common with $\lbrace 1, 2 \rbrace$. This means that the probability that there is one element common between $\lbrace 1, 2 \rbrace$ and the set chosen randomly from $T_1$ is $2/3$. Similarly, the set $\lbrace 1, 2, 3 \rbrace$ in $T_3$ has two elements common with $\lbrace 1, 2 \rbrace$, and the probability that there are exactly two elements common between $\lbrace 1, 2 \rbrace$ and the set chosen randomly from $T_3$ is $1$.
I am aware of the hypergeometric distribution which compares the sets of the same length. But, in this problem, I wish to find the common elements between sets of different lengths.